What is the estimated blood alcohol content (BAC) of a 160-pound man who drinks five 12-ounce beers over a two-hour period?

What is the estimated blood alcohol content (BAC) of a 160-pound man who drinks five 12-ounce beers over a two-hour period?

• A. 0.02
• B. 0.04
• C. 0.06
• D. 0.08

Answer: (C)

To determine the estimated blood alcohol content (BAC) for a 160-pound man consuming five 12-ounce beers over two hours, it's important to understand how alcohol consumption translates into BAC. Each 12-ounce beer generally contains approximately 0.54 ounces of pure alcohol. If the man drinks five beers, that totals about 2.7 ounces of pure alcohol consumed. Typically, a rough formula to estimate BAC is: \[ \text{BAC} = \frac{(\text{Ounces of alcohol} \times 100) \div (\text{Body weight in pounds} \times r)} - (\text{Metabolism rate} \times \text{Hours}) \] The variable 'r' typically represents the alcohol distribution ratio, which is around 0.68 for men. The average rate of alcohol metabolism is about 0.015 per hour. Plugging the numbers in: 1. Calculate BAC from alcohol consumed: \[ \text{BAC from Alcohol} = \frac{(2.7 \text{ ounces} \times 100)}{(160 \text{ pounds} \times 0.68)} \] This reveals that the initial BAC before any metabolism can be

To determine the estimated blood alcohol content (BAC) for a 160-pound man consuming five 12-ounce beers over two hours, it's important to understand how alcohol consumption translates into BAC.

Each 12-ounce beer generally contains approximately 0.54 ounces of pure alcohol. If the man drinks five beers, that totals about 2.7 ounces of pure alcohol consumed.

Typically, a rough formula to estimate BAC is:

[ \text{BAC} = \frac{(\text{Ounces of alcohol} \times 100) \div (\text{Body weight in pounds} \times r)} - (\text{Metabolism rate} \times \text{Hours}) ]

The variable 'r' typically represents the alcohol distribution ratio, which is around 0.68 for men. The average rate of alcohol metabolism is about 0.015 per hour.

Plugging the numbers in:

1. Calculate BAC from alcohol consumed:

[

\text{BAC from Alcohol} = \frac{(2.7 \text{ ounces} \times 100)}{(160 \text{ pounds} \times 0.68)}

]

This reveals that the initial BAC before any metabolism can be